Val
Converts a string to a floating point number
Declare Function Val Overload ( ByRef str As Const String ) As Double
Declare Function Val ( ByRef str As Const WString ) As Double
result = Val( strnum )
strnum
Returns a converted Double precision number
If the first character of the string is invalid, Val will return 0.
Val("10") will return 10.0, and Val("10.10") will return 10.1. The function parses the string from the left, skipping any white space, and returns the longest number it can read, stopping at the first non-suitable character it finds. Scientific notation is recognized, with "D" or "E" used to specify the exponent.
Val can be used to convert integer numbers in binary / octal / hexadecimal format, if they have the relevant identifier ("&B" / "&O" / "&H") prefixed, for example: Val("&HFF") returns 255.
Note:
If you want to get an integer value from a string, consider using ValInt or ValLng instead. They are faster, since they don't use floating-point numbers, and only ValLng provides full 64-bit precision for LongInt types.
If you want to convert a number into string format, use the Str function.
Syntax
Declare Function Val Overload ( ByRef str As Const String ) As Double
Declare Function Val ( ByRef str As Const WString ) As Double
Usage
result = Val( strnum )
Parameters
strnum
the string containing a number to convert
Return Value
Returns a converted Double precision number
If the first character of the string is invalid, Val will return 0.
Description
Val("10") will return 10.0, and Val("10.10") will return 10.1. The function parses the string from the left, skipping any white space, and returns the longest number it can read, stopping at the first non-suitable character it finds. Scientific notation is recognized, with "D" or "E" used to specify the exponent.
Val can be used to convert integer numbers in binary / octal / hexadecimal format, if they have the relevant identifier ("&B" / "&O" / "&H") prefixed, for example: Val("&HFF") returns 255.
Note:
If you want to get an integer value from a string, consider using ValInt or ValLng instead. They are faster, since they don't use floating-point numbers, and only ValLng provides full 64-bit precision for LongInt types.
If you want to convert a number into string format, use the Str function.
Example
Dim a As String, b As Double
a = "2.1E+30xa211"
b = Val(a)
Print a, b
a = "2.1E+30xa211"
b = Val(a)
Print a, b
2.1E+30xa211 2.1e+030
Differences from QB
- None
See also
