Gets an interval from a date
Syntax
Usage
#include "vbcompat.bi"
result = DatePart( interval, date_serial, first_dayofWeek [, first_week_of_year ] )
Parameters
interval
string indicating which part of the date is required
date_serial
the date serial to decode
firstdayofweek
first day of the week
firstdayofyear
first day of the year
Return Value
Return an integer representing the
interval in the
Date Serial.
Description
interval string indicating which part of the date is required is specified as follows:
value | interval |
yyyy | years |
q | quarter(three months) |
m | months |
w | weekday |
ww | week of the year |
y | day of the year |
d | day of the month |
h | hours |
n | minutes |
s | seconds |
first_dayofweek Affects the output when 'w' interval is required.
value | first day of week | constant |
omitted | sunday | |
0 | local settings | fbUseSystem |
1 | sunday | fbSunday |
2 | monday | fbMonday |
3 | tuesday | fbTuesday |
4 | wednesday | fbWednesday |
5 | thursday | fbThursday |
6 | friday | fbFriday |
7 | saturday | fbSaturday |
first_weekofyear specifies which year (previous or next) that the week which spans the end of one year and the beginning of the next should included with. Affects the output when
'ww' interval is required.
value | first week of year | constant |
0 | local settings | fbUseSystem |
1 | January 1's week | fbFirstJan1 |
2 | first weeks having 4 days in the year | fbFirstFourDays |
3 | first full week of year | fbFirstFullWeek |
The compiler will not recognize this function unless
vbcompat.bi or
datetime.bi is included.
Example
#include "vbcompat.bi"
Dim d As Double
d = Now()
Print "Today is day " & DatePart( "y", d );
Print " in week " & DatePart( "ww", d );
Print " of the year " & DatePart( "yyyy", d )
Differences from QB
- Did not exist in QB. This function appeared in Visual Basic.
See also